Base | Representation |
---|---|
bin | 101110111101001100000110… |
… | …0011011100111110000010011 |
3 | 2000011102021201012012021211212 |
4 | 1131322120030123213300103 |
5 | 413114041002042220301 |
6 | 4022235213350530335 |
7 | 152666302160464205 |
oct | 13572301433476023 |
9 | 2004367635167755 |
10 | 413030033554451 |
11 | 10a6710652a8375 |
12 | 3a3a7ba26669ab |
13 | 14960746519061 |
14 | 73dca90330775 |
15 | 32b3cd431b4bb |
hex | 177a60c6e7c13 |
413030033554451 has 2 divisors, whose sum is σ = 413030033554452. Its totient is φ = 413030033554450.
The previous prime is 413030033554441. The next prime is 413030033554499. The reversal of 413030033554451 is 154455330030314.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-413030033554451 is a prime.
It is a super-2 number, since 2×4130300335544512 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 413030033554399 and 413030033554408.
It is not a weakly prime, because it can be changed into another prime (413030033554441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206515016777225 + 206515016777226.
It is an arithmetic number, because the mean of its divisors is an integer number (206515016777226).
Almost surely, 2413030033554451 is an apocalyptic number.
413030033554451 is a deficient number, since it is larger than the sum of its proper divisors (1).
413030033554451 is an equidigital number, since it uses as much as digits as its factorization.
413030033554451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 413030033554451 its reverse (154455330030314), we get a palindrome (567485363584765).
The spelling of 413030033554451 in words is "four hundred thirteen trillion, thirty billion, thirty-three million, five hundred fifty-four thousand, four hundred fifty-one".
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