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4130341214231 is a prime number
BaseRepresentation
bin111100000110101011100…
…001010101100000010111
3112121212010120200102111002
4330012223201111200113
51020132414322323411
612441241430333515
7604256464023131
oct74065341254027
915555116612432
104130341214231
111352738a35031
125685a2aba29b
1323c64959b47b
14103ca3c6a051
157268dc6e33b
hex3c1ab855817

4130341214231 has 2 divisors, whose sum is σ = 4130341214232. Its totient is φ = 4130341214230.

The previous prime is 4130341214227. The next prime is 4130341214257. The reversal of 4130341214231 is 1324121430314.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4130341214231 - 22 = 4130341214227 is a prime.

It is a super-2 number, since 2×41303412142312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4130341214194 and 4130341214203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4130341214221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065170607115 + 2065170607116.

It is an arithmetic number, because the mean of its divisors is an integer number (2065170607116).

Almost surely, 24130341214231 is an apocalyptic number.

4130341214231 is a deficient number, since it is larger than the sum of its proper divisors (1).

4130341214231 is an equidigital number, since it uses as much as digits as its factorization.

4130341214231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4130341214231 its reverse (1324121430314), we get a palindrome (5454462644545).

The spelling of 4130341214231 in words is "four trillion, one hundred thirty billion, three hundred forty-one million, two hundred fourteen thousand, two hundred thirty-one".