Base | Representation |
---|---|
bin | 1100000001010111100… |
… | …01100110111001001111 |
3 | 1110111011020212100100101 |
4 | 12000223301212321033 |
5 | 23231412112110241 |
6 | 513430402311531 |
7 | 41561536664545 |
oct | 6005361467117 |
9 | 1414136770311 |
10 | 413051285071 |
11 | 14a1a0756007 |
12 | 680760585a7 |
13 | 2cc48528329 |
14 | 15dc567bd95 |
15 | ab275cae31 |
hex | 602bc66e4f |
413051285071 has 2 divisors, whose sum is σ = 413051285072. Its totient is φ = 413051285070.
The previous prime is 413051285057. The next prime is 413051285083. The reversal of 413051285071 is 170582150314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 413051285071 - 25 = 413051285039 is a prime.
It is a super-2 number, since 2×4130512850712 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 413051285071.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413051285371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206525642535 + 206525642536.
It is an arithmetic number, because the mean of its divisors is an integer number (206525642536).
Almost surely, 2413051285071 is an apocalyptic number.
413051285071 is a deficient number, since it is larger than the sum of its proper divisors (1).
413051285071 is an equidigital number, since it uses as much as digits as its factorization.
413051285071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33600, while the sum is 37.
The spelling of 413051285071 in words is "four hundred thirteen billion, fifty-one million, two hundred eighty-five thousand, seventy-one".
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