Base | Representation |
---|---|
bin | 10010110010010001111100… |
… | …10100111010100110000011 |
3 | 12102021012102210102101002121 |
4 | 21121020332110322212003 |
5 | 20403310431011420303 |
6 | 223505323152025111 |
7 | 11462360220623656 |
oct | 1131107624724603 |
9 | 172235383371077 |
10 | 41310041123203 |
11 | 12187543299796 |
12 | 47721b5232197 |
13 | 1a0869ba4a208 |
14 | a2b5b944d89d |
15 | 4b98804249bd |
hex | 25923e53a983 |
41310041123203 has 2 divisors, whose sum is σ = 41310041123204. Its totient is φ = 41310041123202.
The previous prime is 41310041123189. The next prime is 41310041123213. The reversal of 41310041123203 is 30232114001314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41310041123203 - 25 = 41310041123171 is a prime.
It is not a weakly prime, because it can be changed into another prime (41310041123213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20655020561601 + 20655020561602.
It is an arithmetic number, because the mean of its divisors is an integer number (20655020561602).
Almost surely, 241310041123203 is an apocalyptic number.
41310041123203 is a deficient number, since it is larger than the sum of its proper divisors (1).
41310041123203 is an equidigital number, since it uses as much as digits as its factorization.
41310041123203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 41310041123203 its reverse (30232114001314), we get a palindrome (71542155124517).
The spelling of 41310041123203 in words is "forty-one trillion, three hundred ten billion, forty-one million, one hundred twenty-three thousand, two hundred three".
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