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413121440041 is a prime number
BaseRepresentation
bin1100000001011111111…
…01001110100100101001
31110111100010212120212121
412000233331032210221
523232033042040131
6513441350111241
741563351205152
oct6005775164451
91414303776777
10413121440041
1114a227312522
126809564b521
132cc59c1c54b
1415dd0b00929
15ab2d837911
hex602ff4e929

413121440041 has 2 divisors, whose sum is σ = 413121440042. Its totient is φ = 413121440040.

The previous prime is 413121439999. The next prime is 413121440047. The reversal of 413121440041 is 140044121314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 215647855641 + 197473584400 = 464379^2 + 444380^2 .

It is a cyclic number.

It is not a de Polignac number, because 413121440041 - 29 = 413121439529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 413121439988 and 413121440015.

It is not a weakly prime, because it can be changed into another prime (413121440047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206560720020 + 206560720021.

It is an arithmetic number, because the mean of its divisors is an integer number (206560720021).

Almost surely, 2413121440041 is an apocalyptic number.

It is an amenable number.

413121440041 is a deficient number, since it is larger than the sum of its proper divisors (1).

413121440041 is an equidigital number, since it uses as much as digits as its factorization.

413121440041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 413121440041 its reverse (140044121314), we get a palindrome (553165561355).

The spelling of 413121440041 in words is "four hundred thirteen billion, one hundred twenty-one million, four hundred forty thousand, forty-one".