Base | Representation |
---|---|
bin | 10010110010010111100011… |
… | …01111111111100100111011 |
3 | 12102021111012120200101120202 |
4 | 21121023301233333210323 |
5 | 20403333112120440123 |
6 | 223510542003312415 |
7 | 11462524632233315 |
oct | 1131136157774473 |
9 | 172244176611522 |
10 | 41313051343163 |
11 | 121888484aa586 |
12 | 47728b537b70b |
13 | 1a08a5b59c462 |
14 | a2b7c31567b5 |
15 | 4b99a9836a28 |
hex | 2592f1bff93b |
41313051343163 has 2 divisors, whose sum is σ = 41313051343164. Its totient is φ = 41313051343162.
The previous prime is 41313051343027. The next prime is 41313051343199. The reversal of 41313051343163 is 36134315031314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41313051343163 - 222 = 41313047148859 is a prime.
It is a super-2 number, since 2×413130513431632 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41313051303163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20656525671581 + 20656525671582.
It is an arithmetic number, because the mean of its divisors is an integer number (20656525671582).
Almost surely, 241313051343163 is an apocalyptic number.
41313051343163 is a deficient number, since it is larger than the sum of its proper divisors (1).
41313051343163 is an equidigital number, since it uses as much as digits as its factorization.
41313051343163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 116640, while the sum is 38.
Adding to 41313051343163 its reverse (36134315031314), we get a palindrome (77447366374477).
The spelling of 41313051343163 in words is "forty-one trillion, three hundred thirteen billion, fifty-one million, three hundred forty-three thousand, one hundred sixty-three".
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