Base | Representation |
---|---|
bin | 111100000111100101010… |
… | …010011111101001100111 |
3 | 112121221122010101021100222 |
4 | 330013211102133221213 |
5 | 1020141410430332101 |
6 | 12441521531354555 |
7 | 604322503003652 |
oct | 74074522375147 |
9 | 15557563337328 |
10 | 4131310402151 |
11 | 1353096023289 |
12 | 5688135b2a5b |
13 | 23c77230ab4a |
14 | 103d56876899 |
15 | 726e8db601b |
hex | 3c1e549fa67 |
4131310402151 has 2 divisors, whose sum is σ = 4131310402152. Its totient is φ = 4131310402150.
The previous prime is 4131310402127. The next prime is 4131310402157. The reversal of 4131310402151 is 1512040131314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4131310402151 - 214 = 4131310385767 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4131310402151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4131310402157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065655201075 + 2065655201076.
It is an arithmetic number, because the mean of its divisors is an integer number (2065655201076).
Almost surely, 24131310402151 is an apocalyptic number.
4131310402151 is a deficient number, since it is larger than the sum of its proper divisors (1).
4131310402151 is an equidigital number, since it uses as much as digits as its factorization.
4131310402151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 4131310402151 its reverse (1512040131314), we get a palindrome (5643350533465).
The spelling of 4131310402151 in words is "four trillion, one hundred thirty-one billion, three hundred ten million, four hundred two thousand, one hundred fifty-one".
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