Base | Representation |
---|---|
bin | 111100000111111110000… |
… | …101110010000100100001 |
3 | 112121222201010100020111012 |
4 | 330013332011302010201 |
5 | 1020143233441001004 |
6 | 12442031114030305 |
7 | 604336014533414 |
oct | 74077605620441 |
9 | 15558633306435 |
10 | 4131726500129 |
11 | 1353289993908 |
12 | 56890aa18395 |
13 | 23c80a597777 |
14 | 103d95c2bb7b |
15 | 727206a946e |
hex | 3c1fe172121 |
4131726500129 has 2 divisors, whose sum is σ = 4131726500130. Its totient is φ = 4131726500128.
The previous prime is 4131726500087. The next prime is 4131726500131. The reversal of 4131726500129 is 9210056271314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3193011610000 + 938714890129 = 1786900^2 + 968873^2 .
It is a cyclic number.
It is not a de Polignac number, because 4131726500129 - 236 = 4063007023393 is a prime.
Together with 4131726500131, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4131726500149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065863250064 + 2065863250065.
It is an arithmetic number, because the mean of its divisors is an integer number (2065863250065).
Almost surely, 24131726500129 is an apocalyptic number.
It is an amenable number.
4131726500129 is a deficient number, since it is larger than the sum of its proper divisors (1).
4131726500129 is an equidigital number, since it uses as much as digits as its factorization.
4131726500129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 41.
The spelling of 4131726500129 in words is "four trillion, one hundred thirty-one billion, seven hundred twenty-six million, five hundred thousand, one hundred twenty-nine".
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