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413301125401 is a prime number
BaseRepresentation
bin1100000001110101010…
…10101011000100011001
31110111210122222112211221
412000322222223010121
523232420042003101
6513511245252041
741600662413163
oct6007252530431
91414718875757
10413301125401
1114a30978a81a
1268125864021
132cc88213148
141600a915933
15ab3e4ccaa1
hex603aaab119

413301125401 has 2 divisors, whose sum is σ = 413301125402. Its totient is φ = 413301125400.

The previous prime is 413301125353. The next prime is 413301125411. The reversal of 413301125401 is 104521103314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 271804779801 + 141496345600 = 521349^2 + 376160^2 .

It is a cyclic number.

It is not a de Polignac number, because 413301125401 - 211 = 413301123353 is a prime.

It is not a weakly prime, because it can be changed into another prime (413301125411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206650562700 + 206650562701.

It is an arithmetic number, because the mean of its divisors is an integer number (206650562701).

Almost surely, 2413301125401 is an apocalyptic number.

It is an amenable number.

413301125401 is a deficient number, since it is larger than the sum of its proper divisors (1).

413301125401 is an equidigital number, since it uses as much as digits as its factorization.

413301125401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 413301125401 its reverse (104521103314), we get a palindrome (517822228715).

The spelling of 413301125401 in words is "four hundred thirteen billion, three hundred one million, one hundred twenty-five thousand, four hundred one".