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413314320017 is a prime number
BaseRepresentation
bin1100000001110110111…
…01000000011010010001
31110111211120210220110102
412000323131000122101
523232431431220032
6513512440142145
741601212516354
oct6007335003221
91414746726412
10413314320017
1114a316182065
126812a167955
132cc8ab82b01
141600c58c29b
15ab40737362
hex603b740691

413314320017 has 2 divisors, whose sum is σ = 413314320018. Its totient is φ = 413314320016.

The previous prime is 413314320011. The next prime is 413314320019. The reversal of 413314320017 is 710023413314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 252441934096 + 160872385921 = 502436^2 + 401089^2 .

It is a cyclic number.

It is not a de Polignac number, because 413314320017 - 222 = 413310125713 is a prime.

It is a super-2 number, since 2×4133143200172 (a number of 24 digits) contains 22 as substring.

Together with 413314320019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (413314320011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206657160008 + 206657160009.

It is an arithmetic number, because the mean of its divisors is an integer number (206657160009).

Almost surely, 2413314320017 is an apocalyptic number.

It is an amenable number.

413314320017 is a deficient number, since it is larger than the sum of its proper divisors (1).

413314320017 is an equidigital number, since it uses as much as digits as its factorization.

413314320017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 29.

The spelling of 413314320017 in words is "four hundred thirteen billion, three hundred fourteen million, three hundred twenty thousand, seventeen".