Base | Representation |
---|---|
bin | 111100001001010110100… |
… | …101010010001011110011 |
3 | 112122010112120222102112201 |
4 | 330021112211102023303 |
5 | 1020204304023400024 |
6 | 12442434311204031 |
7 | 604420553062015 |
oct | 74112645221363 |
9 | 15563476872481 |
10 | 4133211153139 |
11 | 1353980a41672 |
12 | 569064076617 |
13 | 23c9b6045483 |
14 | 1040970981b5 |
15 | 727aabc1744 |
hex | 3c2569522f3 |
4133211153139 has 2 divisors, whose sum is σ = 4133211153140. Its totient is φ = 4133211153138.
The previous prime is 4133211153119. The next prime is 4133211153179. The reversal of 4133211153139 is 9313511123314.
It is a happy number.
4133211153139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4133211153139 - 27 = 4133211153011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4133211153098 and 4133211153107.
It is not a weakly prime, because it can be changed into another prime (4133211153119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066605576569 + 2066605576570.
It is an arithmetic number, because the mean of its divisors is an integer number (2066605576570).
Almost surely, 24133211153139 is an apocalyptic number.
4133211153139 is a deficient number, since it is larger than the sum of its proper divisors (1).
4133211153139 is an equidigital number, since it uses as much as digits as its factorization.
4133211153139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 29160, while the sum is 37.
The spelling of 4133211153139 in words is "four trillion, one hundred thirty-three billion, two hundred eleven million, one hundred fifty-three thousand, one hundred thirty-nine".
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