Base | Representation |
---|---|
bin | 111100001001010111001… |
… | …000100100000010000001 |
3 | 112122010120020101021121111 |
4 | 330021113020210002001 |
5 | 1020204313410320111 |
6 | 12442435241323321 |
7 | 604421024510356 |
oct | 74112710440201 |
9 | 15563506337544 |
10 | 4133220401281 |
11 | 1353986188964 |
12 | 569067196541 |
13 | 23c9b7c32a4a |
14 | 1040983c462d |
15 | 727ab8eba21 |
hex | 3c257224081 |
4133220401281 has 2 divisors, whose sum is σ = 4133220401282. Its totient is φ = 4133220401280.
The previous prime is 4133220401273. The next prime is 4133220401351. The reversal of 4133220401281 is 1821040223314.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3281677171600 + 851543229681 = 1811540^2 + 922791^2 .
It is a cyclic number.
It is not a de Polignac number, because 4133220401281 - 23 = 4133220401273 is a prime.
It is a super-2 number, since 2×41332204012812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4133220401081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066610200640 + 2066610200641.
It is an arithmetic number, because the mean of its divisors is an integer number (2066610200641).
Almost surely, 24133220401281 is an apocalyptic number.
It is an amenable number.
4133220401281 is a deficient number, since it is larger than the sum of its proper divisors (1).
4133220401281 is an equidigital number, since it uses as much as digits as its factorization.
4133220401281 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 4133220401281 its reverse (1821040223314), we get a palindrome (5954260624595).
The spelling of 4133220401281 in words is "four trillion, one hundred thirty-three billion, two hundred twenty million, four hundred one thousand, two hundred eighty-one".
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