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4133220401281 is a prime number
BaseRepresentation
bin111100001001010111001…
…000100100000010000001
3112122010120020101021121111
4330021113020210002001
51020204313410320111
612442435241323321
7604421024510356
oct74112710440201
915563506337544
104133220401281
111353986188964
12569067196541
1323c9b7c32a4a
141040983c462d
15727ab8eba21
hex3c257224081

4133220401281 has 2 divisors, whose sum is σ = 4133220401282. Its totient is φ = 4133220401280.

The previous prime is 4133220401273. The next prime is 4133220401351. The reversal of 4133220401281 is 1821040223314.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3281677171600 + 851543229681 = 1811540^2 + 922791^2 .

It is a cyclic number.

It is not a de Polignac number, because 4133220401281 - 23 = 4133220401273 is a prime.

It is a super-2 number, since 2×41332204012812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4133220401081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066610200640 + 2066610200641.

It is an arithmetic number, because the mean of its divisors is an integer number (2066610200641).

Almost surely, 24133220401281 is an apocalyptic number.

It is an amenable number.

4133220401281 is a deficient number, since it is larger than the sum of its proper divisors (1).

4133220401281 is an equidigital number, since it uses as much as digits as its factorization.

4133220401281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 4133220401281 its reverse (1821040223314), we get a palindrome (5954260624595).

The spelling of 4133220401281 in words is "four trillion, one hundred thirty-three billion, two hundred twenty million, four hundred one thousand, two hundred eighty-one".