Base | Representation |
---|---|
bin | 10010110010111101101010… |
… | …11010111101110000011001 |
3 | 12102100110000122211210121121 |
4 | 21121132311122331300121 |
5 | 20404202014043043301 |
6 | 223524204302005241 |
7 | 11464151003234554 |
oct | 1131366532756031 |
9 | 172313018753547 |
10 | 41333514034201 |
11 | 12196499123194 |
12 | 4776866276821 |
13 | 1a0a96ca9846c |
14 | a2c7a4a8169b |
15 | 4ba2a5eeb3a1 |
hex | 2597b56bdc19 |
41333514034201 has 2 divisors, whose sum is σ = 41333514034202. Its totient is φ = 41333514034200.
The previous prime is 41333514034157. The next prime is 41333514034231. The reversal of 41333514034201 is 10243041533314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30536112350601 + 10797401683600 = 5525949^2 + 3285940^2 .
It is a cyclic number.
It is not a de Polignac number, because 41333514034201 - 215 = 41333514001433 is a prime.
It is not a weakly prime, because it can be changed into another prime (41333514034231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20666757017100 + 20666757017101.
It is an arithmetic number, because the mean of its divisors is an integer number (20666757017101).
Almost surely, 241333514034201 is an apocalyptic number.
It is an amenable number.
41333514034201 is a deficient number, since it is larger than the sum of its proper divisors (1).
41333514034201 is an equidigital number, since it uses as much as digits as its factorization.
41333514034201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 41333514034201 its reverse (10243041533314), we get a palindrome (51576555567515).
The spelling of 41333514034201 in words is "forty-one trillion, three hundred thirty-three billion, five hundred fourteen million, thirty-four thousand, two hundred one".
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