Base | Representation |
---|---|
bin | 10010110011001001110000… |
… | …10000101001001111011111 |
3 | 12102101001202222001212201111 |
4 | 21121210320100221033133 |
5 | 20404303312023030302 |
6 | 223531200302522451 |
7 | 11464500561051325 |
oct | 1131447020511737 |
9 | 172331688055644 |
10 | 41340004111327 |
11 | 12199219653199 |
12 | 4777b77896427 |
13 | 1a0b46555389c |
14 | a2cc1c9c1d15 |
15 | 4ba535b8c0d7 |
hex | 2599384293df |
41340004111327 has 2 divisors, whose sum is σ = 41340004111328. Its totient is φ = 41340004111326.
The previous prime is 41340004111309. The next prime is 41340004111363. The reversal of 41340004111327 is 72311140004314.
41340004111327 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41340004111327 - 243 = 32543911089119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41340004111127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20670002055663 + 20670002055664.
It is an arithmetic number, because the mean of its divisors is an integer number (20670002055664).
Almost surely, 241340004111327 is an apocalyptic number.
41340004111327 is a deficient number, since it is larger than the sum of its proper divisors (1).
41340004111327 is an equidigital number, since it uses as much as digits as its factorization.
41340004111327 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
The spelling of 41340004111327 in words is "forty-one trillion, three hundred forty billion, four million, one hundred eleven thousand, three hundred twenty-seven".
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