4134013001051 has 2 divisors, whose sum is σ = 4134013001052. Its totient is φ = 4134013001050.

The previous prime is 4134013001023. The next prime is 4134013001147. The reversal of 4134013001051 is 1501003104314.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4134013001051 - 2⁶ = 4134013000987 is a prime.

It is not a weakly prime, because it can be changed into another prime (4134013091051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067006500525 + 2067006500526.

It is an arithmetic number, because the mean of its divisors is an integer number (2067006500526).

Almost surely, 2^{4134013001051} is an apocalyptic number.

4134013001051 is a deficient number, since it is larger than the sum of its proper divisors (1).

4134013001051 is an equidigital number, since it uses as much as digits as its factorization.

4134013001051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 4134013001051 its reverse (1501003104314), we get a palindrome (5635016105365).

The spelling of 4134013001051 in words is "four trillion, one hundred thirty-four billion, thirteen million, one thousand, fifty-one".