413403220141 has 4 divisors (see below), whose sum is σ = 413912965984. Its totient is φ = 412893474300.

The previous prime is 413403220073. The next prime is 413403220147. The reversal of 413403220141 is 141022304314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141022304314 = 2 ⋅70511152157.

It is a cyclic number.

It is not a de Polignac number, because 413403220141 - 2¹¹ = 413403218093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (413403220147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254871705 + ... + 254873326.

It is an arithmetic number, because the mean of its divisors is an integer number (103478241496).

Almost surely, 2^413403220141 is an apocalyptic number.

It is an amenable number.

413403220141 is a deficient number, since it is larger than the sum of its proper divisors (509745843).

413403220141 is an equidigital number, since it uses as much as digits as its factorization.

413403220141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 509745842.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 413403220141 its reverse (141022304314), we get a palindrome (554425524455).

The spelling of 413403220141 in words is "four hundred thirteen billion, four hundred three million, two hundred twenty thousand, one hundred forty-one".