Base | Representation |
---|---|
bin | 10010110011001011101000… |
… | …10010100010000011110001 |
3 | 12102101011101011011021101002 |
4 | 21121211310102202003301 |
5 | 20404312342334123103 |
6 | 223531444241051345 |
7 | 11464534540360133 |
oct | 1131456422420361 |
9 | 172334334137332 |
10 | 41341011239153 |
11 | 121996960a523a |
12 | 47781b9026b55 |
13 | 1a0b5960b8202 |
14 | a2ccb6667053 |
15 | 4ba5942ca488 |
hex | 2599744a20f1 |
41341011239153 has 2 divisors, whose sum is σ = 41341011239154. Its totient is φ = 41341011239152.
The previous prime is 41341011239147. The next prime is 41341011239167. The reversal of 41341011239153 is 35193211014314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 26458915055329 + 14882096183824 = 5143823^2 + 3857732^2 .
It is a cyclic number.
It is not a de Polignac number, because 41341011239153 - 216 = 41341011173617 is a prime.
It is not a weakly prime, because it can be changed into another prime (41341011239123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20670505619576 + 20670505619577.
It is an arithmetic number, because the mean of its divisors is an integer number (20670505619577).
Almost surely, 241341011239153 is an apocalyptic number.
It is an amenable number.
41341011239153 is a deficient number, since it is larger than the sum of its proper divisors (1).
41341011239153 is an equidigital number, since it uses as much as digits as its factorization.
41341011239153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 38.
The spelling of 41341011239153 in words is "forty-one trillion, three hundred forty-one billion, eleven million, two hundred thirty-nine thousand, one hundred fifty-three".
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