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41341134003 = 3134371347209
BaseRepresentation
bin100110100000000111…
…111010010010110011
310221201010122012111020
4212200013322102303
51134131312242003
630554123550523
72662320561321
oct464007722263
9127633565436
1041341134003
1116594aa0954
12801908b443
133b8ab90290
142002758d11
15111e5eed53
hex9a01fa4b3

41341134003 has 32 divisors (see below), whose sum is σ = 61597831680. Its totient is φ = 24498996480.

The previous prime is 41341134001. The next prime is 41341134011. The reversal of 41341134003 is 30043114314.

It is not a de Polignac number, because 41341134003 - 21 = 41341134001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (41341134001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 54538 + ... + 292671.

It is an arithmetic number, because the mean of its divisors is an integer number (1924932240).

Almost surely, 241341134003 is an apocalyptic number.

41341134003 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

41341134003 is a deficient number, since it is larger than the sum of its proper divisors (20256697677).

41341134003 is a wasteful number, since it uses less digits than its factorization.

41341134003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 347339.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 41341134003 its reverse (30043114314), we get a palindrome (71384248317).

The spelling of 41341134003 in words is "forty-one billion, three hundred forty-one million, one hundred thirty-four thousand, three".

Divisors: 1 3 13 39 43 71 129 213 559 923 1677 2769 3053 9159 39689 119067 347209 1041627 4513717 13541151 14929987 24651839 44789961 73955517 194089831 320473907 582269493 961421721 1060029077 3180087231 13780378001 41341134003