41341210000001 has 4 divisors (see below), whose sum is σ = 43773045882372. Its totient is φ = 38909374117632.

The previous prime is 41341209999997. The next prime is 41341210000033. The reversal of 41341210000001 is 10000001214314.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 16426646880400 + 24914563119601 = 4052980^2 + 4991449^2 .

It is a cyclic number.

It is not a de Polignac number, because 41341210000001 - 2² = 41341209999997 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 2431835882353 = 41341210000001 / (4 + 1 + 3 + 4 + 1 + 2 + 1 + 0 + 0 + 0 + 0 + 0 + 0 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41341210000201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1215917941160 + ... + 1215917941193.

It is an arithmetic number, because the mean of its divisors is an integer number (10943261470593).

Almost surely, 2^{41341210000001} is an apocalyptic number.

It is an amenable number.

41341210000001 is a deficient number, since it is larger than the sum of its proper divisors (2431835882371).

41341210000001 is a wasteful number, since it uses less digits than its factorization.

41341210000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2431835882370.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 41341210000001 its reverse (10000001214314), we get a palindrome (51341211214315).

The spelling of 41341210000001 in words is "forty-one trillion, three hundred forty-one billion, two hundred ten million, one", and thus it is an aban number.