413412140041 has 2 divisors, whose sum is σ = 413412140042. Its totient is φ = 413412140040.

The previous prime is 413412140023. The next prime is 413412140051. The reversal of 413412140041 is 140041214314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 338292293641 + 75119846400 = 581629^2 + 274080^2 .

It is a cyclic number.

It is not a de Polignac number, because 413412140041 - 2¹¹ = 413412137993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 413412139988 and 413412140015.

It is not a weakly prime, because it can be changed into another prime (413412140051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206706070020 + 206706070021.

It is an arithmetic number, because the mean of its divisors is an integer number (206706070021).

Almost surely, 2^413412140041 is an apocalyptic number.

It is an amenable number.

413412140041 is a deficient number, since it is larger than the sum of its proper divisors (1).

413412140041 is an equidigital number, since it uses as much as digits as its factorization.

413412140041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 413412140041 its reverse (140041214314), we get a palindrome (553453354355).

The spelling of 413412140041 in words is "four hundred thirteen billion, four hundred twelve million, one hundred forty thousand, forty-one".