Base | Representation |
---|---|
bin | 111100001010001110000… |
… | …101011111000000010111 |
3 | 112122012221111011200100022 |
4 | 330022032011133000113 |
5 | 1020213210414404033 |
6 | 12443110533535355 |
7 | 604452621044603 |
oct | 74121605370027 |
9 | 15565844150308 |
10 | 4134142341143 |
11 | 1354309635a31 |
12 | 569283aa455b |
13 | 23cb03c3b7a9 |
14 | 104144a12503 |
15 | 7281280e098 |
hex | 3c28e15f017 |
4134142341143 has 2 divisors, whose sum is σ = 4134142341144. Its totient is φ = 4134142341142.
The previous prime is 4134142341097. The next prime is 4134142341227. The reversal of 4134142341143 is 3411432414314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4134142341143 - 218 = 4134142078999 is a prime.
It is a super-2 number, since 2×41341423411432 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4134142340143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067071170571 + 2067071170572.
It is an arithmetic number, because the mean of its divisors is an integer number (2067071170572).
Almost surely, 24134142341143 is an apocalyptic number.
4134142341143 is a deficient number, since it is larger than the sum of its proper divisors (1).
4134142341143 is an equidigital number, since it uses as much as digits as its factorization.
4134142341143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 35.
Adding to 4134142341143 its reverse (3411432414314), we get a palindrome (7545574755457).
The spelling of 4134142341143 in words is "four trillion, one hundred thirty-four billion, one hundred forty-two million, three hundred forty-one thousand, one hundred forty-three".
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