Base | Representation |
---|---|
bin | 111100001010011000101… |
… | …011010110110110110001 |
3 | 112122020101212112210021001 |
4 | 330022120223112312301 |
5 | 1020214041412311033 |
6 | 12443140322402001 |
7 | 604460206344253 |
oct | 74123053266661 |
9 | 15566355483231 |
10 | 4134320041393 |
11 | 135439a977843 |
12 | 569313500301 |
13 | 23cb319b8979 |
14 | 10416046bcd3 |
15 | 72823210e7d |
hex | 3c298ad6db1 |
4134320041393 has 2 divisors, whose sum is σ = 4134320041394. Its totient is φ = 4134320041392.
The previous prime is 4134320041391. The next prime is 4134320041433. The reversal of 4134320041393 is 3931400234314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3969526262689 + 164793778704 = 1992367^2 + 405948^2 .
It is a cyclic number.
It is not a de Polignac number, because 4134320041393 - 21 = 4134320041391 is a prime.
Together with 4134320041391, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4134320041391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067160020696 + 2067160020697.
It is an arithmetic number, because the mean of its divisors is an integer number (2067160020697).
Almost surely, 24134320041393 is an apocalyptic number.
It is an amenable number.
4134320041393 is a deficient number, since it is larger than the sum of its proper divisors (1).
4134320041393 is an equidigital number, since it uses as much as digits as its factorization.
4134320041393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 37.
The spelling of 4134320041393 in words is "four trillion, one hundred thirty-four billion, three hundred twenty million, forty-one thousand, three hundred ninety-three".
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