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4134435323173 is a prime number
BaseRepresentation
bin111100001010011111100…
…011000111110100100101
3112122020200220110201010121
4330022133203013310211
51020214310420320143
612443200001321541
7604463106254611
oct74123743076445
915566626421117
104134435323173
111354449a56741
125693460362b1
1323cb4c85013c
141041718ba341
157282d3d37ed
hex3c29f8c7d25

4134435323173 has 2 divisors, whose sum is σ = 4134435323174. Its totient is φ = 4134435323172.

The previous prime is 4134435323143. The next prime is 4134435323219. The reversal of 4134435323173 is 3713235344314.

4134435323173 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4112715048289 + 21720274884 = 2027983^2 + 147378^2 .

It is a cyclic number.

It is not a de Polignac number, because 4134435323173 - 237 = 3996996369701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4134435323143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067217661586 + 2067217661587.

It is an arithmetic number, because the mean of its divisors is an integer number (2067217661587).

Almost surely, 24134435323173 is an apocalyptic number.

It is an amenable number.

4134435323173 is a deficient number, since it is larger than the sum of its proper divisors (1).

4134435323173 is an equidigital number, since it uses as much as digits as its factorization.

4134435323173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1088640, while the sum is 43.

The spelling of 4134435323173 in words is "four trillion, one hundred thirty-four billion, four hundred thirty-five million, three hundred twenty-three thousand, one hundred seventy-three".