Base | Representation |
---|---|
bin | 111100001011000001100… |
… | …000101100111111010011 |
3 | 112122022011121122002122112 |
4 | 330023001200230333103 |
5 | 1020221442302124243 |
6 | 12443332314055535 |
7 | 604513165355366 |
oct | 74130140547723 |
9 | 15568147562575 |
10 | 4135005114323 |
11 | 1354711651216 |
12 | 569484a1a5ab |
13 | 23cc108cc975 |
14 | 1041c743c0dd |
15 | 72863435818 |
hex | 3c2c182cfd3 |
4135005114323 has 2 divisors, whose sum is σ = 4135005114324. Its totient is φ = 4135005114322.
The previous prime is 4135005114277. The next prime is 4135005114329. The reversal of 4135005114323 is 3234115005314.
4135005114323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4135005114323 - 214 = 4135005097939 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4135005114323.
It is not a weakly prime, because it can be changed into another prime (4135005114329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067502557161 + 2067502557162.
It is an arithmetic number, because the mean of its divisors is an integer number (2067502557162).
Almost surely, 24135005114323 is an apocalyptic number.
4135005114323 is a deficient number, since it is larger than the sum of its proper divisors (1).
4135005114323 is an equidigital number, since it uses as much as digits as its factorization.
4135005114323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 32.
The spelling of 4135005114323 in words is "four trillion, one hundred thirty-five billion, five million, one hundred fourteen thousand, three hundred twenty-three".
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