Base | Representation |
---|---|
bin | 1100000010001101010… |
… | …10111001010101001101 |
3 | 1110112022200220222011002 |
4 | 12001012222321111031 |
5 | 23233323120313123 |
6 | 513543241510045 |
7 | 41605656226406 |
oct | 6010652712515 |
9 | 1415280828132 |
10 | 413502510413 |
11 | 14a402429313 |
12 | 681811a2325 |
13 | 2ccbab63985 |
14 | 160295789ad |
15 | ab5200c528 |
hex | 6046ab954d |
413502510413 has 2 divisors, whose sum is σ = 413502510414. Its totient is φ = 413502510412.
The previous prime is 413502510331. The next prime is 413502510439. The reversal of 413502510413 is 314015205314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 292678836004 + 120823674409 = 540998^2 + 347597^2 .
It is a cyclic number.
It is not a de Polignac number, because 413502510413 - 214 = 413502494029 is a prime.
It is a super-2 number, since 2×4135025104132 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413502500413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206751255206 + 206751255207.
It is an arithmetic number, because the mean of its divisors is an integer number (206751255207).
Almost surely, 2413502510413 is an apocalyptic number.
It is an amenable number.
413502510413 is a deficient number, since it is larger than the sum of its proper divisors (1).
413502510413 is an equidigital number, since it uses as much as digits as its factorization.
413502510413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 413502510413 its reverse (314015205314), we get a palindrome (727517715727).
The spelling of 413502510413 in words is "four hundred thirteen billion, five hundred two million, five hundred ten thousand, four hundred thirteen".
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