413513000437 has 2 divisors, whose sum is σ = 413513000438. Its totient is φ = 413513000436.

The previous prime is 413513000429. The next prime is 413513000441. The reversal of 413513000437 is 734000315314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 412788260196 + 724740241 = 642486^2 + 26921^2 .

It is a cyclic number.

It is not a de Polignac number, because 413513000437 - 2³ = 413513000429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 413513000399 and 413513000408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413513000477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206756500218 + 206756500219.

It is an arithmetic number, because the mean of its divisors is an integer number (206756500219).

Almost surely, 2^413513000437 is an apocalyptic number.

It is an amenable number.

413513000437 is a deficient number, since it is larger than the sum of its proper divisors (1).

413513000437 is an equidigital number, since it uses as much as digits as its factorization.

413513000437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 31.

The spelling of 413513000437 in words is "four hundred thirteen billion, five hundred thirteen million, four hundred thirty-seven", and thus it is an aban number.