Base | Representation |
---|---|
bin | 101111000000111110011000… |
… | …1010011100100011010110111 |
3 | 2000020021000201110200002202221 |
4 | 1132001330301103210122313 |
5 | 413201102100332242242 |
6 | 4023314223245143211 |
7 | 153052012012043044 |
oct | 13601746123443267 |
9 | 2006230643602687 |
10 | 413550343243447 |
11 | 10a851796586803 |
12 | 3a4709b125ab07 |
13 | 1499a826252687 |
14 | 7419d2ca121cb |
15 | 32c25d7e90167 |
hex | 1781f314e46b7 |
413550343243447 has 2 divisors, whose sum is σ = 413550343243448. Its totient is φ = 413550343243446.
The previous prime is 413550343243417. The next prime is 413550343243571. The reversal of 413550343243447 is 744342343055314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 413550343243447 - 231 = 413548195759799 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 413550343243394 and 413550343243403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413550343243417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206775171621723 + 206775171621724.
It is an arithmetic number, because the mean of its divisors is an integer number (206775171621724).
Almost surely, 2413550343243447 is an apocalyptic number.
413550343243447 is a deficient number, since it is larger than the sum of its proper divisors (1).
413550343243447 is an equidigital number, since it uses as much as digits as its factorization.
413550343243447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29030400, while the sum is 52.
The spelling of 413550343243447 in words is "four hundred thirteen trillion, five hundred fifty billion, three hundred forty-three million, two hundred forty-three thousand, four hundred forty-seven".
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