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413595012401 is a prime number
BaseRepresentation
bin1100000010011000010…
…11110000110100110001
31110112120010222120000122
412001030023300310301
523234020310344101
6514000344300025
741611161412454
oct6011413606461
91415503876018
10413595012401
1114a44a66943a
12681a8171615
133000408068c
141603797749b
15ab5a1d051b
hex604c2f0d31

413595012401 has 2 divisors, whose sum is σ = 413595012402. Its totient is φ = 413595012400.

The previous prime is 413595012323. The next prime is 413595012403. The reversal of 413595012401 is 104210595314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 413326839025 + 268173376 = 642905^2 + 16376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-413595012401 is a prime.

Together with 413595012403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (413595012403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206797506200 + 206797506201.

It is an arithmetic number, because the mean of its divisors is an integer number (206797506201).

Almost surely, 2413595012401 is an apocalyptic number.

It is an amenable number.

413595012401 is a deficient number, since it is larger than the sum of its proper divisors (1).

413595012401 is an equidigital number, since it uses as much as digits as its factorization.

413595012401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 413595012401 in words is "four hundred thirteen billion, five hundred ninety-five million, twelve thousand, four hundred one".