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41365377984 = 263783601617
BaseRepresentation
bin100110100001100100…
…011001001111000000
310221202211020220222110
4212201210121033000
51134204014043414
631000351335320
72663033624430
oct464144311700
9127684226873
1041365377984
11165a774a7a7
128025221540
133b92bcb328
142005a6a2c0
1511217dd459
hex9a19193c0

41365377984 has 224 divisors, whose sum is σ = 127004161536. Its totient is φ = 11637964800.

The previous prime is 41365377929. The next prime is 41365377997. The reversal of 41365377984 is 48977356314.

It is a tau number, because it is divible by the number of its divisors (224).

It is a super-2 number, since 2×413653779842 (a number of 22 digits) contains 22 as substring.

Its product of digits (15240960) is a multiple of the sum of its prime factors (1323).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 67042444 + ... + 67043060.

It is an arithmetic number, because the mean of its divisors is an integer number (566982864).

Almost surely, 241365377984 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 41365377984, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (63502080768).

41365377984 is an abundant number, since it is smaller than the sum of its proper divisors (85638783552).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

41365377984 is a wasteful number, since it uses less digits than its factorization.

41365377984 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1323 (or 1313 counting only the distinct ones).

The product of its digits is 15240960, while the sum is 57.

The spelling of 41365377984 in words is "forty-one billion, three hundred sixty-five million, three hundred seventy-seven thousand, nine hundred eighty-four".