Base | Representation |
---|---|
bin | 111100001110100111111… |
… | …100010011011000001101 |
3 | 112122200011001011222112111 |
4 | 330032213330103120031 |
5 | 1020302402000443013 |
6 | 12445212055504021 |
7 | 605011040650315 |
oct | 74164774233015 |
9 | 15580131158474 |
10 | 4138871109133 |
11 | 1356315928352 |
12 | 56a183688011 |
13 | 2403a8832867 |
14 | 104472a6c445 |
15 | 729dca3a73d |
hex | 3c3a7f1360d |
4138871109133 has 2 divisors, whose sum is σ = 4138871109134. Its totient is φ = 4138871109132.
The previous prime is 4138871109103. The next prime is 4138871109161. The reversal of 4138871109133 is 3319011788314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2319172631689 + 1819698477444 = 1522883^2 + 1348962^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4138871109133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4138871109103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2069435554566 + 2069435554567.
It is an arithmetic number, because the mean of its divisors is an integer number (2069435554567).
Almost surely, 24138871109133 is an apocalyptic number.
It is an amenable number.
4138871109133 is a deficient number, since it is larger than the sum of its proper divisors (1).
4138871109133 is an equidigital number, since it uses as much as digits as its factorization.
4138871109133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 435456, while the sum is 49.
The spelling of 4138871109133 in words is "four trillion, one hundred thirty-eight billion, eight hundred seventy-one million, one hundred nine thousand, one hundred thirty-three".
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