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41390471 is a prime number
BaseRepresentation
bin1001110111100…
…1000110000111
32212212212001102
42131321012013
541043443341
64035050315
71011545633
oct235710607
985785042
1041390471
1121400301
1211a4099b
138762705
1456d5dc3
153978c9b
hex2779187

41390471 has 2 divisors, whose sum is σ = 41390472. Its totient is φ = 41390470.

The previous prime is 41390441. The next prime is 41390477. The reversal of 41390471 is 17409314.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41390471 - 218 = 41128327 is a prime.

It is a super-3 number, since 3×413904713 (a number of 24 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41390477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20695235 + 20695236.

It is an arithmetic number, because the mean of its divisors is an integer number (20695236).

Almost surely, 241390471 is an apocalyptic number.

41390471 is a deficient number, since it is larger than the sum of its proper divisors (1).

41390471 is an equidigital number, since it uses as much as digits as its factorization.

41390471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 29.

The square root of 41390471 is about 6433.5426477175. The cubic root of 41390471 is about 345.9129248401.

Adding to 41390471 its reverse (17409314), we get a palindrome (58799785).

It can be divided in two parts, 41 and 390471, that multiplied together give a triangular number (16009311 = T5658).

The spelling of 41390471 in words is "forty-one million, three hundred ninety thousand, four hundred seventy-one".