Base | Representation |
---|---|
bin | 10010110100111001100001… |
… | …11101001110111001011001 |
3 | 12102120210122221211222110221 |
4 | 21122130300331032321121 |
5 | 20411244210321434223 |
6 | 224014522541240041 |
7 | 11502023604205132 |
oct | 1132346075167131 |
9 | 172523587758427 |
10 | 41400011124313 |
11 | 12211711a90206 |
12 | 4787723b63021 |
13 | 1a14009597b6a |
14 | a31ab237cc89 |
15 | 4bbd98d27b5d |
hex | 25a730f4ee59 |
41400011124313 has 2 divisors, whose sum is σ = 41400011124314. Its totient is φ = 41400011124312.
The previous prime is 41400011124301. The next prime is 41400011124319. The reversal of 41400011124313 is 31342111000414.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 35108326851984 + 6291684272329 = 5925228^2 + 2508323^2 .
It is a cyclic number.
It is not a de Polignac number, because 41400011124313 - 25 = 41400011124281 is a prime.
It is not a weakly prime, because it can be changed into another prime (41400011124319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20700005562156 + 20700005562157.
It is an arithmetic number, because the mean of its divisors is an integer number (20700005562157).
Almost surely, 241400011124313 is an apocalyptic number.
It is an amenable number.
41400011124313 is a deficient number, since it is larger than the sum of its proper divisors (1).
41400011124313 is an equidigital number, since it uses as much as digits as its factorization.
41400011124313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 41400011124313 its reverse (31342111000414), we get a palindrome (72742122124727).
The spelling of 41400011124313 in words is "forty-one trillion, four hundred billion, eleven million, one hundred twenty-four thousand, three hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •