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414012013453 is a prime number
BaseRepresentation
bin1100000011001010000…
…10011111101110001101
31110120122012122101221001
412001211002133232031
523240344033412303
6514110002140301
741624414023123
oct6014502375615
91416565571831
10414012013453
1114a643a96505
12682a3951691
133006c59536c
14160770c5913
15ab81b0131d
hex606509fb8d

414012013453 has 2 divisors, whose sum is σ = 414012013454. Its totient is φ = 414012013452.

The previous prime is 414012013403. The next prime is 414012013469. The reversal of 414012013453 is 354310210414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 375129300484 + 38882712969 = 612478^2 + 197187^2 .

It is a cyclic number.

It is not a de Polignac number, because 414012013453 - 221 = 414009916301 is a prime.

It is a super-3 number, since 3×4140120134533 (a number of 36 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (414012013403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207006006726 + 207006006727.

It is an arithmetic number, because the mean of its divisors is an integer number (207006006727).

Almost surely, 2414012013453 is an apocalyptic number.

It is an amenable number.

414012013453 is a deficient number, since it is larger than the sum of its proper divisors (1).

414012013453 is an equidigital number, since it uses as much as digits as its factorization.

414012013453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 414012013453 its reverse (354310210414), we get a palindrome (768322223867).

The spelling of 414012013453 in words is "four hundred fourteen billion, twelve million, thirteen thousand, four hundred fifty-three".