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414014343131 is a prime number
BaseRepresentation
bin1100000011001010010…
…11011000011111011011
31110120122101000202122102
412001211023120133123
523240400132440011
6514110124114015
741624442565154
oct6014513303733
91416571022572
10414014343131
1114a645337864
12682a469590b
133006cbcc87c
141607753092b
15ab81e1173b
hex60652d87db

414014343131 has 2 divisors, whose sum is σ = 414014343132. Its totient is φ = 414014343130.

The previous prime is 414014343109. The next prime is 414014343133. The reversal of 414014343131 is 131343410414.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-414014343131 is a prime.

It is a super-2 number, since 2×4140143431312 (a number of 24 digits) contains 22 as substring.

Together with 414014343133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 414014343094 and 414014343103.

It is not a weakly prime, because it can be changed into another prime (414014343133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207007171565 + 207007171566.

It is an arithmetic number, because the mean of its divisors is an integer number (207007171566).

Almost surely, 2414014343131 is an apocalyptic number.

414014343131 is a deficient number, since it is larger than the sum of its proper divisors (1).

414014343131 is an equidigital number, since it uses as much as digits as its factorization.

414014343131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 414014343131 its reverse (131343410414), we get a palindrome (545357753545).

The spelling of 414014343131 in words is "four hundred fourteen billion, fourteen million, three hundred forty-three thousand, one hundred thirty-one".