Search a number
-
+
414015552113 is a prime number
BaseRepresentation
bin1100000011001010011…
…11111111101001110001
31110120122110022012001112
412001211033333221301
523240400440131423
6514110210043105
741624456061662
oct6014517775161
91416573265045
10414015552113
1114a645a93119
12682a4b79495
1330070233c47
1416077767369
15ab8209ea78
hex60653ffa71

414015552113 has 2 divisors, whose sum is σ = 414015552114. Its totient is φ = 414015552112.

The previous prime is 414015552109. The next prime is 414015552131. The reversal of 414015552113 is 311255510414.

Together with next prime (414015552131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 407371998049 + 6643554064 = 638257^2 + 81508^2 .

It is a cyclic number.

It is not a de Polignac number, because 414015552113 - 22 = 414015552109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 414015552113.

It is not a weakly prime, because it can be changed into another prime (414015552103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207007776056 + 207007776057.

It is an arithmetic number, because the mean of its divisors is an integer number (207007776057).

Almost surely, 2414015552113 is an apocalyptic number.

It is an amenable number.

414015552113 is a deficient number, since it is larger than the sum of its proper divisors (1).

414015552113 is an equidigital number, since it uses as much as digits as its factorization.

414015552113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 32.

The spelling of 414015552113 in words is "four hundred fourteen billion, fifteen million, five hundred fifty-two thousand, one hundred thirteen".