Base | Representation |
---|---|
bin | 111100001111111101110… |
… | …110111011001101000011 |
3 | 112122210212111111020220211 |
4 | 330033331312323031003 |
5 | 1020313330002234341 |
6 | 12450011110414551 |
7 | 605061542630506 |
oct | 74177566731503 |
9 | 15583774436824 |
10 | 4140312539971 |
11 | 1356995544703 |
12 | 56a506361457 |
13 | 24057835920a |
14 | 10456c28713d |
15 | 72a74366181 |
hex | 3c3fddbb343 |
4140312539971 has 2 divisors, whose sum is σ = 4140312539972. Its totient is φ = 4140312539970.
The previous prime is 4140312539861. The next prime is 4140312540011. The reversal of 4140312539971 is 1799352130414.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4140312539971 is a prime.
It is a super-2 number, since 2×41403125399712 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4140312539771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2070156269985 + 2070156269986.
It is an arithmetic number, because the mean of its divisors is an integer number (2070156269986).
Almost surely, 24140312539971 is an apocalyptic number.
4140312539971 is a deficient number, since it is larger than the sum of its proper divisors (1).
4140312539971 is an equidigital number, since it uses as much as digits as its factorization.
4140312539971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 816480, while the sum is 49.
The spelling of 4140312539971 in words is "four trillion, one hundred forty billion, three hundred twelve million, five hundred thirty-nine thousand, nine hundred seventy-one".
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