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41404142113 is a prime number
BaseRepresentation
bin100110100011111000…
…010001001000100001
310221212112012100100221
4212203320101020201
51134243430021423
631004254243041
72664014254405
oct464370211041
9127775170327
1041404142113
1116617616874
1280361b6481
133b9ac51499
14200ac7b105
151124de8e5d
hex9a3e11221

41404142113 has 2 divisors, whose sum is σ = 41404142114. Its totient is φ = 41404142112.

The previous prime is 41404142099. The next prime is 41404142149. The reversal of 41404142113 is 31124140414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 41399227024 + 4915089 = 203468^2 + 2217^2 .

It is a cyclic number.

It is not a de Polignac number, because 41404142113 - 221 = 41402044961 is a prime.

It is a super-2 number, since 2×414041421132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41404122113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20702071056 + 20702071057.

It is an arithmetic number, because the mean of its divisors is an integer number (20702071057).

Almost surely, 241404142113 is an apocalyptic number.

It is an amenable number.

41404142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

41404142113 is an equidigital number, since it uses as much as digits as its factorization.

41404142113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 41404142113 its reverse (31124140414), we get a palindrome (72528282527).

The spelling of 41404142113 in words is "forty-one billion, four hundred four million, one hundred forty-two thousand, one hundred thirteen".