Base | Representation |
---|---|
bin | 111100010000101001010… |
… | …111000111111101111111 |
3 | 112122212202100212001020101 |
4 | 330100221113013331333 |
5 | 1020321323323314101 |
6 | 12450211342101531 |
7 | 605115614431615 |
oct | 74205127077577 |
9 | 15585670761211 |
10 | 4141042401151 |
11 | 135722a52a167 |
12 | 56a68a87a8a7 |
13 | 240663622336 |
14 | 1045db1956b5 |
15 | 72ab8486401 |
hex | 3c4295c7f7f |
4141042401151 has 2 divisors, whose sum is σ = 4141042401152. Its totient is φ = 4141042401150.
The previous prime is 4141042401137. The next prime is 4141042401163. The reversal of 4141042401151 is 1511042401414.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4141042401151 - 239 = 3591286587263 is a prime.
It is a super-2 number, since 2×41410424011512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4141042401451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2070521200575 + 2070521200576.
It is an arithmetic number, because the mean of its divisors is an integer number (2070521200576).
Almost surely, 24141042401151 is an apocalyptic number.
4141042401151 is a deficient number, since it is larger than the sum of its proper divisors (1).
4141042401151 is an equidigital number, since it uses as much as digits as its factorization.
4141042401151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 28.
Adding to 4141042401151 its reverse (1511042401414), we get a palindrome (5652084802565).
The spelling of 4141042401151 in words is "four trillion, one hundred forty-one billion, forty-two million, four hundred one thousand, one hundred fifty-one".
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