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41413199981 is a prime number
BaseRepresentation
bin100110100100011010…
…110100100001101101
310221220011020112102112
4212210122310201231
51134303234344411
631005220333405
72664154251236
oct464432644155
9127804215375
1041413199981
111662174310a
128039244265
133b9caa327a
14200c15808d
151125ad7b8b
hex9a46b486d

41413199981 has 2 divisors, whose sum is σ = 41413199982. Its totient is φ = 41413199980.

The previous prime is 41413199929. The next prime is 41413200029. The reversal of 41413199981 is 18999131414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40898590756 + 514609225 = 202234^2 + 22685^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41413199981 is a prime.

It is a super-2 number, since 2×414131999812 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41413199921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20706599990 + 20706599991.

It is an arithmetic number, because the mean of its divisors is an integer number (20706599991).

Almost surely, 241413199981 is an apocalyptic number.

It is an amenable number.

41413199981 is a deficient number, since it is larger than the sum of its proper divisors (1).

41413199981 is an equidigital number, since it uses as much as digits as its factorization.

41413199981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 279936, while the sum is 50.

The spelling of 41413199981 in words is "forty-one billion, four hundred thirteen million, one hundred ninety-nine thousand, nine hundred eighty-one".