Base | Representation |
---|---|
bin | 10010110101010010101011… |
… | …00111111100010101010111 |
3 | 12102122002111210121222202020 |
4 | 21122221111213330111113 |
5 | 20412004332331432020 |
6 | 224025034314544223 |
7 | 11503012262032452 |
oct | 1132512547742527 |
9 | 172562453558666 |
10 | 41413511202135 |
11 | 1221740a475516 |
12 | 478a271138073 |
13 | 1a1537b44b1a7 |
14 | a325d32c0499 |
15 | 4bc3d910ac40 |
hex | 25aa559fc557 |
41413511202135 has 32 divisors (see below), whose sum is σ = 66945598517952. Its totient is φ = 21859218370560.
The previous prime is 41413511202001. The next prime is 41413511202163. The reversal of 41413511202135 is 53120211531414.
It is not a de Polignac number, because 41413511202135 - 221 = 41413509104983 is a prime.
It is a super-2 number, since 2×414135112021352 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41413511202096 and 41413511202105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 158203777 + ... + 158465333.
It is an arithmetic number, because the mean of its divisors is an integer number (2092049953686).
Almost surely, 241413511202135 is an apocalyptic number.
41413511202135 is a deficient number, since it is larger than the sum of its proper divisors (25532087315817).
41413511202135 is a wasteful number, since it uses less digits than its factorization.
41413511202135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 370483.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 41413511202135 its reverse (53120211531414), we get a palindrome (94533722733549).
The spelling of 41413511202135 in words is "forty-one trillion, four hundred thirteen billion, five hundred eleven million, two hundred two thousand, one hundred thirty-five".
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