Base | Representation |
---|---|
bin | 10010110101110011010010… |
… | …11110000101100100010001 |
3 | 12102200202201022002221000012 |
4 | 21122321221132011210101 |
5 | 20412301214123011032 |
6 | 224041052155404305 |
7 | 11504202253444514 |
oct | 1132715136054421 |
9 | 172622638087005 |
10 | 41431024032017 |
11 | 12223886a63844 |
12 | 479173a153695 |
13 | 1a16c0c769319 |
14 | a333b5134d7b |
15 | 4bcab18326b2 |
hex | 25ae69785911 |
41431024032017 has 2 divisors, whose sum is σ = 41431024032018. Its totient is φ = 41431024032016.
The previous prime is 41431024031981. The next prime is 41431024032067. The reversal of 41431024032017 is 71023042013414.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24992410576081 + 16438613455936 = 4999241^2 + 4054456^2 .
It is a cyclic number.
It is not a de Polignac number, because 41431024032017 - 210 = 41431024030993 is a prime.
It is not a weakly prime, because it can be changed into another prime (41431024032067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20715512016008 + 20715512016009.
It is an arithmetic number, because the mean of its divisors is an integer number (20715512016009).
Almost surely, 241431024032017 is an apocalyptic number.
It is an amenable number.
41431024032017 is a deficient number, since it is larger than the sum of its proper divisors (1).
41431024032017 is an equidigital number, since it uses as much as digits as its factorization.
41431024032017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
The spelling of 41431024032017 in words is "forty-one trillion, four hundred thirty-one billion, twenty-four million, thirty-two thousand, seventeen".
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