Base | Representation |
---|---|
bin | 111100010010110010011… |
… | …101000011010011011101 |
3 | 112200002200122202210110201 |
4 | 330102302131003103131 |
5 | 1020341031130333001 |
6 | 12451231503503501 |
7 | 605226613406365 |
oct | 74226235032335 |
9 | 15602618683421 |
10 | 4143342433501 |
11 | 13581aa872547 |
12 | 56b010bb7b91 |
13 | 24093bca911b |
14 | 1047788319a5 |
15 | 72ba0362501 |
hex | 3c4b27434dd |
4143342433501 has 2 divisors, whose sum is σ = 4143342433502. Its totient is φ = 4143342433500.
The previous prime is 4143342433369. The next prime is 4143342433513. The reversal of 4143342433501 is 1053342433414.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3991308726276 + 152033707225 = 1997826^2 + 389915^2 .
It is a cyclic number.
It is not a de Polignac number, because 4143342433501 - 233 = 4134752498909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4143342433541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2071671216750 + 2071671216751.
It is an arithmetic number, because the mean of its divisors is an integer number (2071671216751).
Almost surely, 24143342433501 is an apocalyptic number.
It is an amenable number.
4143342433501 is a deficient number, since it is larger than the sum of its proper divisors (1).
4143342433501 is an equidigital number, since it uses as much as digits as its factorization.
4143342433501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 37.
Adding to 4143342433501 its reverse (1053342433414), we get a palindrome (5196684866915).
The spelling of 4143342433501 in words is "four trillion, one hundred forty-three billion, three hundred forty-two million, four hundred thirty-three thousand, five hundred one".
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