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414334431253 is a prime number
BaseRepresentation
bin1100000011110000100…
…00011011000000010101
31110121110200022221000001
412001320100123000111
523242024103300003
6514202000451301
741635410361531
oct6017020330025
91417420287001
10414334431253
1114a799a917a6
1268373919b31
13300c1311c22
14160a7c52bc1
15aba008c61d
hex607841b015

414334431253 has 2 divisors, whose sum is σ = 414334431254. Its totient is φ = 414334431252.

The previous prime is 414334431241. The next prime is 414334431331. The reversal of 414334431253 is 352134433414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 340503759729 + 73830671524 = 583527^2 + 271718^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-414334431253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (414334431233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207167215626 + 207167215627.

It is an arithmetic number, because the mean of its divisors is an integer number (207167215627).

Almost surely, 2414334431253 is an apocalyptic number.

It is an amenable number.

414334431253 is a deficient number, since it is larger than the sum of its proper divisors (1).

414334431253 is an equidigital number, since it uses as much as digits as its factorization.

414334431253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 207360, while the sum is 37.

Adding to 414334431253 its reverse (352134433414), we get a palindrome (766468864667).

The spelling of 414334431253 in words is "four hundred fourteen billion, three hundred thirty-four million, four hundred thirty-one thousand, two hundred fifty-three".