Base | Representation |
---|---|
bin | 111100010011110001100… |
… | …011101011001001111111 |
3 | 112200012102102220100210222 |
4 | 330103301203223021333 |
5 | 1020400213142243312 |
6 | 12451524523251555 |
7 | 605265060253355 |
oct | 74236143531177 |
9 | 15605372810728 |
10 | 4144401134207 |
11 | 13586a343a004 |
12 | 56b267679bbb |
13 | 240a7a429a49 |
14 | 10483929d7d5 |
15 | 72c1328b672 |
hex | 3c4f18eb27f |
4144401134207 has 2 divisors, whose sum is σ = 4144401134208. Its totient is φ = 4144401134206.
The previous prime is 4144401134191. The next prime is 4144401134257. The reversal of 4144401134207 is 7024311044414.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4144401134207 - 24 = 4144401134191 is a prime.
It is a super-2 number, since 2×41444011342072 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4144401134257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072200567103 + 2072200567104.
It is an arithmetic number, because the mean of its divisors is an integer number (2072200567104).
Almost surely, 24144401134207 is an apocalyptic number.
4144401134207 is a deficient number, since it is larger than the sum of its proper divisors (1).
4144401134207 is an equidigital number, since it uses as much as digits as its factorization.
4144401134207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43008, while the sum is 35.
The spelling of 4144401134207 in words is "four trillion, one hundred forty-four billion, four hundred one million, one hundred thirty-four thousand, two hundred seven".
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