Base | Representation |
---|---|
bin | 100110100111100010… |
… | …000100110000101011 |
3 | 10222000210112020211122 |
4 | 212213202010300223 |
5 | 1134410122330011 |
6 | 31014324045455 |
7 | 2665360236413 |
oct | 464742046053 |
9 | 128023466748 |
10 | 41465433131 |
11 | 16649179701 |
12 | 805283388b |
13 | 3baa860c65 |
14 | 2015073643 |
15 | 112a4a43db |
hex | 9a7884c2b |
41465433131 has 2 divisors, whose sum is σ = 41465433132. Its totient is φ = 41465433130.
The previous prime is 41465433103. The next prime is 41465433197. The reversal of 41465433131 is 13133456414.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41465433131 - 218 = 41465170987 is a prime.
It is a super-2 number, since 2×414654331312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41465433091 and 41465433100.
It is not a weakly prime, because it can be changed into another prime (41465432131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20732716565 + 20732716566.
It is an arithmetic number, because the mean of its divisors is an integer number (20732716566).
Almost surely, 241465433131 is an apocalyptic number.
41465433131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41465433131 is an equidigital number, since it uses as much as digits as its factorization.
41465433131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51840, while the sum is 35.
Adding to 41465433131 its reverse (13133456414), we get a palindrome (54598889545).
The spelling of 41465433131 in words is "forty-one billion, four hundred sixty-five million, four hundred thirty-three thousand, one hundred thirty-one".
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