Base | Representation |
---|---|
bin | 1100000100111101101… |
… | …00100011111111101111 |
3 | 1110200010202210100102101 |
4 | 12002132310203333233 |
5 | 23244340222030341 |
6 | 514350112235531 |
7 | 41660425015054 |
oct | 6023664437757 |
9 | 1420122710371 |
10 | 414981439471 |
11 | 14aaa1227635 |
12 | 6851453bba7 |
13 | 30195389221 |
14 | 16129b5502b |
15 | abdbc93831 |
hex | 609ed23fef |
414981439471 has 2 divisors, whose sum is σ = 414981439472. Its totient is φ = 414981439470.
The previous prime is 414981439459. The next prime is 414981439489. The reversal of 414981439471 is 174934189414.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 414981439471 - 27 = 414981439343 is a prime.
It is a super-3 number, since 3×4149814394713 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (414981439441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207490719735 + 207490719736.
It is an arithmetic number, because the mean of its divisors is an integer number (207490719736).
Almost surely, 2414981439471 is an apocalyptic number.
414981439471 is a deficient number, since it is larger than the sum of its proper divisors (1).
414981439471 is an equidigital number, since it uses as much as digits as its factorization.
414981439471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3483648, while the sum is 55.
The spelling of 414981439471 in words is "four hundred fourteen billion, nine hundred eighty-one million, four hundred thirty-nine thousand, four hundred seventy-one".
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