Base | Representation |
---|---|
bin | 1100000100111111110… |
… | …11100010001011010001 |
3 | 1110200012001210120100221 |
4 | 12002133323202023101 |
5 | 23244410002403431 |
6 | 514352015113041 |
7 | 41661042113266 |
oct | 6023773421321 |
9 | 1420161716327 |
10 | 415000044241 |
11 | 150000784682 |
12 | 6851a812781 |
13 | 301991a1573 |
14 | 1612c3d926d |
15 | abdd71b111 |
hex | 609fee22d1 |
415000044241 has 2 divisors, whose sum is σ = 415000044242. Its totient is φ = 415000044240.
The previous prime is 415000044223. The next prime is 415000044307. The reversal of 415000044241 is 142440000514.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 383359105600 + 31640938641 = 619160^2 + 177879^2 .
It is a cyclic number.
It is not a de Polignac number, because 415000044241 - 29 = 415000043729 is a prime.
It is a super-3 number, since 3×4150000442413 (a number of 36 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (415000048241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207500022120 + 207500022121.
It is an arithmetic number, because the mean of its divisors is an integer number (207500022121).
Almost surely, 2415000044241 is an apocalyptic number.
It is an amenable number.
415000044241 is a deficient number, since it is larger than the sum of its proper divisors (1).
415000044241 is an equidigital number, since it uses as much as digits as its factorization.
415000044241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 415000044241 its reverse (142440000514), we get a palindrome (557440044755).
The spelling of 415000044241 in words is "four hundred fifteen billion, forty-four thousand, two hundred forty-one".
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