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4153221430213 is a prime number
BaseRepresentation
bin111100011011111111010…
…010011011101111000101
3112201001012010211211021211
4330123333102123233011
51021021244141231323
612455544045011421
7606026461451152
oct74337722335705
915631163754254
104153221430213
11136140a24aa39
12570b09553b71
132418548aaacb
14105034897229
157307c7bc70d
hex3c6ff49bbc5

4153221430213 has 2 divisors, whose sum is σ = 4153221430214. Its totient is φ = 4153221430212.

The previous prime is 4153221430139. The next prime is 4153221430219. The reversal of 4153221430213 is 3120341223514.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3723348441604 + 429872988609 = 1929598^2 + 655647^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4153221430213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4153221430219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2076610715106 + 2076610715107.

It is an arithmetic number, because the mean of its divisors is an integer number (2076610715107).

Almost surely, 24153221430213 is an apocalyptic number.

It is an amenable number.

4153221430213 is a deficient number, since it is larger than the sum of its proper divisors (1).

4153221430213 is an equidigital number, since it uses as much as digits as its factorization.

4153221430213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 4153221430213 its reverse (3120341223514), we get a palindrome (7273562653727).

The spelling of 4153221430213 in words is "four trillion, one hundred fifty-three billion, two hundred twenty-one million, four hundred thirty thousand, two hundred thirteen".