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41537113 is a prime number
BaseRepresentation
bin1001111001110…
…0111001011001
32220011022012121
42132130321121
541113141423
64042141241
71013026312
oct236347131
986138177
1041537113
11214a04a2
1211ab1821
1387b4397
145733609
1539a745d
hex279ce59

41537113 has 2 divisors, whose sum is σ = 41537114. Its totient is φ = 41537112.

The previous prime is 41537099. The next prime is 41537131. The reversal of 41537113 is 31173514.

Together with next prime (41537131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34609689 + 6927424 = 5883^2 + 2632^2 .

It is a cyclic number.

It is not a de Polignac number, because 41537113 - 25 = 41537081 is a prime.

It is not a weakly prime, because it can be changed into another prime (41537413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20768556 + 20768557.

It is an arithmetic number, because the mean of its divisors is an integer number (20768557).

Almost surely, 241537113 is an apocalyptic number.

It is an amenable number.

41537113 is a deficient number, since it is larger than the sum of its proper divisors (1).

41537113 is an equidigital number, since it uses as much as digits as its factorization.

41537113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1260, while the sum is 25.

The square root of 41537113 is about 6444.9292470903. The cubic root of 41537113 is about 346.3209541496.

The spelling of 41537113 in words is "forty-one million, five hundred thirty-seven thousand, one hundred thirteen".