Base | Representation |
---|---|
bin | 1111011110101110… |
… | …1000111111010001 |
3 | 101201121010211020012 |
4 | 3313223220333101 |
5 | 32002241144213 |
6 | 1524200524305 |
7 | 204655265024 |
oct | 36753507721 |
9 | 11647124205 |
10 | 4155412433 |
11 | 1842692957 |
12 | 97b780695 |
13 | 512b97033 |
14 | 2b5c4b1bb |
15 | 194c234a8 |
hex | f7ae8fd1 |
4155412433 has 2 divisors, whose sum is σ = 4155412434. Its totient is φ = 4155412432.
The previous prime is 4155412351. The next prime is 4155412439. The reversal of 4155412433 is 3342145514.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4042797889 + 112614544 = 63583^2 + 10612^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4155412433 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4155412433.
It is not a weakly prime, because it can be changed into another prime (4155412439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2077706216 + 2077706217.
It is an arithmetic number, because the mean of its divisors is an integer number (2077706217).
Almost surely, 24155412433 is an apocalyptic number.
It is an amenable number.
4155412433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4155412433 is an equidigital number, since it uses as much as digits as its factorization.
4155412433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 28800, while the sum is 32.
The square root of 4155412433 is about 64462.4885728126. The cubic root of 4155412433 is about 1607.6988889051.
Adding to 4155412433 its reverse (3342145514), we get a palindrome (7497557947).
The spelling of 4155412433 in words is "four billion, one hundred fifty-five million, four hundred twelve thousand, four hundred thirty-three".
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